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Friedmann Equations

The dependence of the scale of the universe, $a(t)$, on time is given by the Friedmann equations for the first and second derivatives of $a$. In physical units the first Friedmann equation in flat spacetime is [1,3,4]

\begin{displaymath}
\left(\frac{\dot{a}}{a}\right)^2 = \frac{\Lambda}{3}
+ \frac{8\pi G \rho_m(t)}{3}
+ \frac{8\pi G \rho_r(t)}{3}
\end{displaymath} (21)

$\Lambda$ is the cosmological constant which is presently interpreted as representing the role of dark energy in the dynamics of the universe. Mass and electromagnetic radiation determine the gravitational energy. $\rho_m(t)$ is the time-dependent mass density, and $\rho_r(t) = u_r/c^2$ is the time-dependent mass equivalent to the radiation energy density $u_r$. The left hand side of this equation gives the rate of expansion of the universe relative to its scale at that moment.

The ratio $\dot{a}/a$ has dimensions of $1/t$. At the present epoch ($t_0$) it is the Hubble Constant $H_0$

\begin{displaymath}
H_0 = \left[\frac{\dot{a}}{a}\right]_{t=t_0}
\end{displaymath} (22)

which is found by measuring the redshift $z$ through Eqs. 5 or 18. If $\dot{a}$ were always constant and equal to its present value, then the age of the universe would be $t_0$ such that
$\displaystyle \frac{da}{dt}$ $\textstyle =$ $\displaystyle a_0 H_0$ (23)
$\displaystyle \int_0^{a_0} da$ $\textstyle =$ $\displaystyle a_0 H_0  \int_0^{t_0}dt$ (24)
$\displaystyle a_0$ $\textstyle =$ $\displaystyle a_0 H_0 t_0$ (25)
$\displaystyle t_0$ $\textstyle =$ $\displaystyle H_0^{-1}$ (26)

Mass density simply scales with the volume of the universe

\begin{displaymath}
\rho_m(t) = \rho_m(t_0) \left( \frac{a_0}{a} \right)^3
\end{displaymath} (27)

but the contribution of radiation density to gravitation also includes the redshift of the photons
\begin{displaymath}
\rho_r(t) = \rho_r(t_0) \left( \frac{a_0}{a} \right)^4
\end{displaymath} (28)

It is useful to measure time in units of $t_0 = H_0^{-1}$, and distance in units of $a_0 = c t_0$. To that end, Eq. 21 becomes
\begin{displaymath}
\left(\frac{\dot{a}}{a}\right)^2 = H_0^2 \left(\frac{\Lambda...
... \pi G}{3 H_0^2} \rho_r \left(\frac{a_0}{a}\right)^4 \right)
\end{displaymath} (29)

A simpler form that shows the time scale explicitly is
\begin{displaymath}
\left(\frac{\dot{a}}{a}\right)^2 = \left(\frac{1}{t_0}\right...
...frac{\Omega_m}{(a/a_0)^3} +
\frac{\Omega_r}{(a/a_0)^4}\right)
\end{displaymath} (30)

where
\begin{displaymath}
\Omega_\Lambda=\frac{\Lambda}{3 H_0^2}
\end{displaymath} (31)


\begin{displaymath}
\Omega_r=\frac{\rho_r(t_0)}{\rho_c}
\end{displaymath} (32)

and
\begin{displaymath}
\Omega_m = \frac{\rho_m(t_0)}{\rho_c}
\end{displaymath} (33)

A Newtonian universe with critical density $\rho_c$ given by
\begin{displaymath}
\rho_c=\frac{3 H_0^2}{8 \pi G}
\end{displaymath} (34)

would stop expanding after an infinite time. The parameters in Eq. 30 determine the past and future of the universe, but they are measured at $t_0$ in the universe today. Gott et al. [1] give values for them based on WMAP measurements of the cosmic background radiation, and an assumption of a flat universe:
$\displaystyle H_0$ $\textstyle =$ $\displaystyle 71 \;\; \mathrm{km}/\mathrm{sec} \mathrm{Mpc}$ (35)
$\displaystyle \Omega_{\Lambda}$ $\textstyle =$ $\displaystyle 0.73$ (36)
$\displaystyle \Omega_r$ $\textstyle =$ $\displaystyle 8.35 \times 10^{-5}$ (37)
$\displaystyle \Omega_m$ $\textstyle =$ $\displaystyle 0.27 - \Omega_r$ (38)
$\displaystyle a_0$ $\textstyle =$ $\displaystyle c t_0 = c/H_0$ (39)


next up previous
Next: Comoving Distance and Lookback Up: Distance Scale Previous: Redshift
John Kielkopf
2005-11-26