- A converging meniscus lens has surfaces whose
radii of curvature are 20 cm and 30 cm. The lens is made
from crown glass whose index of refraction is 1.5. Find its focal
length.
1/f = (n-1)(1/R1
+ 1/R2)
1/f = (1.5 -
1)(1/20 - 1/30)
1/f = 0.5 x (1/60)
= 1/120
f = 120 cm
- The index of refraction of crown glass is 1.523
for blue light and 1.517 for red light. How far apart are the
focal points for blue and red light of a plano-convex lens of crown
glass whose radius of curvature is 200
mm ?
1/f = (n-1)(1/R1
+ 1/R2)
1/fblue
= (1.523 - 1)(1/200) =
0.523/200
fblue =
200/0.523 = 382.4 mm
1/fred
= (1.517 - 1)(1/200) = 0.517/200
fred =
200/0.517 = 386.8 mm
fred - fblue
= 386.8 -
382.4
= 4.4 mm
- Both surfaces of a double-concave lens whose
focal length is -18 cm have radii of 20 cm. Find the index
of refraction of the glass.
1/f = (n-1)(1/R1
+ 1/R2)
R1 = R2
= R = -20 cm
n = 1 + R/2f = 1 +
(-20)/(-18 x 2)
n = 1.555
- A plano-concave lens of focal length 90 mm is to
be ground from quartz of index of refraction 1.55. Find
the required radius of curvature.
1/f = (n-1)(1/R1
+ 1/R2)
1/R1 = 0
R2
=(n-1)f = (1.55-1) x (-90) = -49.5 mm