Heat Engines: Kelvin and Clausius Statements



"Computer Science is no more about computers than astronomy is about telescopes."

E. W. Dijkstra

It is impossible to extract an amount of heat QH from a hot reservoir and use it all to do work W . Some amount of heat QC must be exhausted to a cold reservoir. This precludes a perfect heat engine.
2nd law fig3
It is not possible for heat to flow from a colder body to a warmer body without any work having been done to accomplish this flow. Energy will not flow spontaneously from a low temperature object to a higher temperature object. This precludes a perfect refrigerator.
2nd law fig2

2nd law eqn1

Since QH > QC and QC is not zero, e < 1.
  • For refrigerators we define the coefficient of performance
2nd law eqn2

exclamationNote that the EER (energy efficiency rating) on air conditioners and refrigerators is the c.o.p in mixed units - (Btu/hr)/Watts.   Since 1 W = 3.413 Btu/hr, then  EER = 3.413 x c.o.p.

exclamation Schematically a heat pump is identical to a refrigerator, but in this case maximizing QH is paramount.  For a heat pump the c.o.p is defined as QH/W.

Early morning Physics class filled with slightly dazed freshmen. Eager beaver postdoc teaching the class asks "The wavelength of the Sodium yellow line. What is it? You there!" Fortunately, he has his eagle eye on the guy next to me, who mutters and replies "A hundred and one?"
"Hah!" says the postdoc "A hundred and one what?"
"Um, a hundred and one, point two?"



 

Dr. C. L. Davis
Physics Department
University of Louisville
email: c.l.davis@louisville.edu